Question: student _ idnameagedept _ id 1 John Smith 2 2 1 2 Mary Johnson 2 0 2 3 David Lee 2 3 1 4 Karen

student_idnameagedept_id1John Smith2212Mary Johnson2023David Lee2314Karen Chen2135Tom Baker194
Choices:
None of the above choices.
SELECT name, age FROM Students WHERE age =(SELECT AVG(age) FROM Students);
SELECT name, age FROM Students WHERE age =(SELECT MIN(age) FROM Students);
SELECT name, age FROM Students WHERE age =(SELECT COUNT(age) FROM Students);
SELECT name, age FROM Students WHERE age =(SELECT MAX(age) FROM Students);

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