Question: Study -{ 0 f(x) = xy(y-ix) x6+y for z 0, = 0. for z = Show that even though [(z) (0)]/z 0 as z
Study -{ 0 f(x) = xy(y-ix) x6+y for z 0, = 0. for z = Show that even though [(z) (0)]/z 0 as z 0 for any straight line through the origin, f(z) is nevertheless not complex differentiable at z = 0. Hint: play around with curves given by cubic equations.
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