subject - computer organization and assemble language

just give a value that goes in blank space

3. Assuming RO contains 0x34000000, R1 contains OxCD1258EF, R2 contains 0x00000002 and 3 contains Ox00000001, write the contents of the memory locations below after the STR instruction writes to memory, assuming that each operation is independent. If a number not known, mark the blank with an "X". a. STR R1, [RO); assuming little endian convention: Value at address 0x34000000 is Value at address 0x34000001 is Value at address 0x34000002 is Value at address Ox34000003 is b. STRH R1. (RO); assuming little-endian convention: Value at address 0x34000000 is Value at address Ox34000001 is Value at address Ox34000002 is Value at address 0x34000003 is C. STRB R1. [RO]: assuming little-endian convention: Value at address 0x34000000 is Value at address 0x34000001 is Value at address 0x34000002 is Value at address 0x34000003 is d. STR R1. (RO): assuming big-endian convention: Value at address 0x34000000 is Value at address Ox34000001 is Value at address 0x34000002 is Value at address 0x34000003 is e. STRH R1. [RO): assuming big-endian convention: Value at address 0x34000000 is Value at address 0x34000001 is Value at address 0x34000002 is Value at address 0x34000003 is f. STRB R1, [RO]: assuming big-endian convention: Value at address 0x34000000 is Value at address 0x34000001 is Value at address 0x34000002 is Value at address 0x34000003 is 9. STRB R1. [RO, R3]: assuming big-endian convention: Value at address 0x34000000 is Value at address 0x34000001 is Value at address Ox34000002 is Value at address 0x34000003 is h. STRH R1, [RO, R2): assuming little-endian convention Value at address Ox34000000 is Value at address Ox34000001 is Value at address Ox34000002 is Value at address 0x34000003 is