Question: 2y/dx + x?dy/dx + 3xdy/dx 5y = sin(x) + xdy/dx? + 3.rdy/dx 5y = sin(x) | Solve the differential equation. I found that m1=1.5260

2y/dx + x?dy/dx + 3xdy/dx 5y = sin(x) + xdy/dx? + 3.rdy/dx

2y/dx + x?dy/dx + 3xdy/dx 5y = sin(x) + xdy/dx? + 3.rdy/dx 5y = sin(x) | Solve the differential equation. I found that m1=1.5260 and m2=0.2370(+-)1.7946i

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