Submission $1(0/6\mathrm{.}76$ points$)$ Wednesday, January $29,202506$:$38$ PM CST Find $(f^{-1}{)}^{\text{'}}(a).$

$f(x)=\sqrt[\phantom{2}]{2x^3+2x^2+4x+1},a=3$

$(f^{-1}{)}^{\text{'}}(a)=$

$x$

Submission $2(0/6\mathrm{.}76$ points$)$ Wednesday, January $29,202506$:$38$ PM CST Find $(f^{-1}{)}^{\text{'}}(a).$

$f(x)=\sqrt[\phantom{2}]{2x^3+2x^2+4x+1},a=3$

Find $(f^{-1}{)}^{\text{'}}(a)$

$f(x)=\sqrt[\phantom{2}]{2x^3+2x^2+4x+1},a=3$

$(f^{-1}{)}^{\text{'}}(a)=$