Using the substitution: u=z+3z-6. Re-write the indefinite integral then evaluate in terms of u. -3x-6 [((-)2...

 

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Using the substitution: u=z²+3z-6. Re-write the indefinite integral then evaluate in terms of u. -3x-6 [((-²)2 + (-²)) ²²+ ³²-6dz = Note: answer should be in terms of u only Back substituting in the antiderivative you found in Part 1. above we have [((-²)² + (-))e²²¹+³²-6 dz = Note: answer should be in terms of I only Using the substitution: u=z²+3z-6. Re-write the indefinite integral then evaluate in terms of u. -3x-6 [((-²)2 + (-²)) ²²+ ³²-6dz = Note: answer should be in terms of u only Back substituting in the antiderivative you found in Part 1. above we have [((-²)² + (-))e²²¹+³²-6 dz = Note: answer should be in terms of I only

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Here are the steps Given u x2 3x 6 dudx 2x 3 Substitute u into ... View the full answer