Question: sum = 0 ; for ( k = 1 ; k < = n; k * = 2 ) for ( j = n; j

sum =0; for (k=1; k<=n; k*=2) for (j=n; j<=1; j/=2)
sum++;
The time complexity of the algorithm is
Select one:
a. O(log n^2)
b. O(logn)
C. O((log n)^2)
d. O(n^2)

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