sume that the surface defines the zero reference point for gravitational potential energy.

Largest total mechanical energy

Smallest total mechanical energy

Answer Bank

$m_1=0\mathrm{.}50kg$;$k_1=500\frac{N}{m}$; amplitude $A=0\mathrm{.}020m$

$m_2=0\mathrm{.}60kg$;$k_2=300\frac{N}{m}$;$v_2=1\mathrm{.}0\frac{m}{s}$ when passing through equilibrium

$m_3=1\mathrm{.}2kg$;$k_3=400\frac{N}{m}$;$v_3=0\mathrm{.}50\frac{m}{s}$ when passing through $x=-0\mathrm{.}010m$

$m_4=2\mathrm{.}0kg$;$k_4=200\frac{N}{m}$;$v_4=0\mathrm{.}20\frac{m}{s}$ when passing through $x=0\mathrm{.}050m$