Suppose 200 mol/s of liquid methanol and 30% excess oxygen are fed to a reactor at...

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Suppose 200 mol/s of liquid methanol and 30% excess oxygen are fed to a reactor at 25°C, a 50% fractional conversion of methanol is obtained, and the products are brought back down to 25°C. You wish to calculate Q (kJ/s). 2CH₂OH(1) + O₂(g) → 2CH₂O(v) + 2H₂O(1) ΔΗ, = -326 kJ Suppose 200 mol/s of liquid methanol and 30% excess oxygen are fed to a reactor at 25°C, a 50% fractional conversion of methanol is obtained, and the products are brought back down to 25°C. You wish to calculate Q (kJ/s). 2CH₂OH(1) + O₂(g) → 2CH₂O(v) + 2H₂O(1) ΔΗ, = -326 kJ

Answer rating: 100% (QA)

The reaction involved is 2CH3OH302 2CO24H20 Thus feed has 20... View the full answer