Question: Suppose a computer using direct mapped cache scheme has 8Kbytes (i.e. 2 13 bytes) of byte-addressable main memory and a cache of 32 blocks, where

Suppose a computer using direct mapped cache scheme has 8Kbytes (i.e. 213 bytes) of byte-addressable main memory and a cache of 32 blocks, where each cache block contains 16 bytes.

a. How many blocks of main memory are there? Please note the size block in main memory is same with the size of block in cache.

b. To which cache block will the memory address 316 map? Please note address 316 is a decimal number and we need to convert it binary

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