Question: Suppose a matrix A with 447 columns has Rank(A) = 385. Then the dimension of the null space of A is: dim (Null(A)) = You

Suppose a matrix A with 447 columns has Rank(A) = 385. Then the dimension of the null space of A is: dim (Null(A)) = You are given a set S of 196 linearly independent vectors in IR30. if V = Span($) and VI is the orthogonal complement of V in R$), then dim(V) dim(V ! )

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