Question: Suppose a second, horizontal spring will be coupled to the cylinder. The second spring is identical to the first one ( i . e .
Suppose a second, horizontal spring will be coupled to the cylinder. The second spring is identical to the first one ie same constant also being considered massless, etc and, again, one end is connected to the cylinder's axle. The only difference is that the second spring is located to the right of the cylinder where it is connected horizontally to a second wall similarly to how the first one is connected to the left wall ie at equilibrium both springs are neither stretched nor compressed
The period of this altered system can be written as
Find the value for the factor and enter its numerical value sig.figs. in the box given below.
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