Question: Suppose a stone is thrown vertically upward from the edge of a cliff on Mars (where the acceleration due to gravity is only about 12
Suppose a stone is thrown vertically upward from the edge of a cliff on Mars (where the acceleration due to gravity is only about 12 ft/s2) with an initial velocity of 64 ft/s from a height of 192ft above the ground. The height s of the stone above the ground (in ft) after t seconds is given by s = 6t2 + 64t + 192.
- Provide the graph of the height function s for t 0.
- When does it reach its maximum height, and what is the maximum height that it reaches?
- If our goal was to double the highest point of the stone please select one element in this scenario you could change that would accomplish that goal. Explain what you would change and how that would impact the calculations.
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