Question: Suppose abc could satisfy the given condition. Since a^2-1 is divisible by b, the numbers a and b are relatively prime. Thus, number c^2-1 that

Suppose abc could satisfy the given condition. Since a^2-1 is divisible by b, the numbers a and b are relatively prime. Thus, number c^2-1 that is divisible by a and b, must be the product of ab, which c^2-1ab. But ac and bc, so abc^2, contradiction

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