Suppose f(x, y) is differentiable. x(s, t) = 5s + 2t +2st +3 and y(s, t)...

Transcribed Image Text:

Suppose f(x, y) is differentiable. x(s, t) = 5s + 2t +2st +3 and y(s, t) = 4s + 3t² + 2. We are given the value of the function f(x, y) and it's partials at (0,0) and (3, 2) in the table below. Let g(s, t) = f(x(s, t), y(s, t)). (ii) (1.25 points) Find g.(0,0). (0,0) (3,2) (i) (1 point) Compute the missing values (a and b) in the table below using the r(s, t) and y(s, t). (s, t) x (0,0) 3 5 2 240 (3,2) 34 a b 26 4 12 (iii) (1.25 points) Find gt(0, 0). ffa fy 3 5 5 -432 Suppose f(x, y) is differentiable. x(s, t) = 5s + 2t +2st +3 and y(s, t) = 4s + 3t² + 2. We are given the value of the function f(x, y) and it's partials at (0,0) and (3, 2) in the table below. Let g(s, t) = f(x(s, t), y(s, t)). (ii) (1.25 points) Find g.(0,0). (0,0) (3,2) (i) (1 point) Compute the missing values (a and b) in the table below using the r(s, t) and y(s, t). (s, t) x (0,0) 3 5 2 240 (3,2) 34 a b 26 4 12 (iii) (1.25 points) Find gt(0, 0). ffa fy 3 5 5 -432