Question: Suppose that a and b are boolean values. Show that the expression (!(a && b) && (a || b)) || ((a && b) || !(a

Suppose that a and b are boolean values.

Show that the expression (!(a && b) && (a || b)) || ((a && b) || !(a || b)) is equivalent to true.

a

b

a && b

a || b

false

false

false

false

false

true

false

true

true

false

false

true

true

true

true

true

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