Suppose that an object is moving along a vertical line. Its vertical position is given by the equation, $s(t)=-t^2-t5$ where distance is measured in meters and time in seconds.

NOTE: Using Desmos will make your work a lot easier and may help you avoid algebraic errors.

A$.$ Compute $s(0\mathrm{.}5)$ and $s(1)$ and explain what they mean.

B$.$ Find the average velocity of the object between $t=0\mathrm{.}5$ and $t=1.$ This can be abbreviated as $A{V}_{[0\mathrm{.}5,1]}.$

C$.$ By taking $t$ values closer and closer to $1$ and calculating the average velocities, find the instantaneous velocity of the object at the instant $t=1$ second. Be sure to state the units.

To do this problem, complete the missing values in the table below. Your answer will be the velocity approached as you move closer and closer to $1.$

$\backslash$table$[[t,s(1)-s(t),A{V}_{[t,1]}$