Suppose that $f(2)=-5,g(2)=3,f^{\text{'}}(2)=-4,$ and $g^{\text{'}}(2)=1.$ Find $h^{\text{'}}(2).$

$($a$)h(x)=2f(x)-4g(x)$

$h^{\text{'}}(2)=$

$($b$),h(x)=f(x)g(x)$

$h^{\text{'}}(2)=$

$($c$),h(x)=\frac{f(x)}{g(x)}$

$h^{\text{'}}(2)=$

$($d$),h(x)=\frac{g(x)}{1+f(x)}$

$h^{\text{'}}(2)=$