Suppose that $f(x)$ is a function given as $f(x)=2x-4x^2.$

Simplify the expression $f(x+h).$

$f(x+h)=$

Simplify the difference quotient, $\frac{f(x+h)-f(x)}{h}.$

$\frac{f(x+h)-f(x)}{h}=$

$$

The derivative of the function at $x$ is the limit of the difference quotient as $h$ approaches zero.

$f^{\text{'}}(x)=\underset{h0}{lim}\frac{f(x+h)-f(x)}{h}=$

$$