Suppose that for a given computer salesperson, the probability distribution ofx= the number of systems sold in1 monthis given by the following table.

x: 12345678

p(x): 0.04, 0.10, 0.13, 0.30, 0.30, 0.11, 0.01, 0.01

(d)

What is the probability that the number of systems sold is more than 2 standard deviations from the mean?

Suppose that for a given computer salesperson, the probability distribution ofX = the number of systems sold in 1 month is given by the following table. X 4 5 6 7 8 P(X) 0.04 0.10 0.13 0.30 0.30 0.11 0.01 0.01 (a) Find the mean value ofX (the mean number of systems sold). 4.12 J (b) Find the variance and standard deviation of X. (Round your standard deviation to four decimal places.) variance standard deviation How would you interpret these values? (Round your standard deviation to four decimal places.) The mean squared deviation from the mean number of systems sold in one month is 1.9456 systems sold in one month is 1.3948 (c) What is the probability that the number of systems sold is within 1 standard deviation of its mean value? .73 J 1 .9456 1 .3948 J J J J . A typical deviation from the mean number of (d) What is the probability that the number of systems sold is more than 2 standard deviations from the mean? .9545 X