Suppose that jobs arrive at a single server queueing system according to a

nonhomogeneous Poisson process whose rate is initially $4$ per hour, increases

steadily until it hits $19$ per hour after $5$ hours, and then decreases steadily

until it hits $4$ per hour after an additional $5$ hours. The rate then repeats

indefinitely in this fashion, that is $\backslash$lambda $($t$+10)=\backslash$lambda $($t$).$ Suppose that the service

distribution is exponential with rate $25$ per hour. Suppose also that whenever

the server completes a service and finds no jobs waiting he goes on break for a

time that is uniformly distributed on $(0,0\mathrm{.}3).$ If upon returning from his break

there are no jobs waiting, then he goes on another break. Use simulation to