Question: Suppose that the PDF of a random variable is as follows: f(x) =either 4/3 * (1-x^3) for for0x1 or 0 otherwise What is the value

Suppose that the PDF of a random variable is as follows:

f(x) =either 4/3 * (1-x^3) for for0x1

or 0 otherwise

What is the value of P(X < 0)?

a) 2/3

b) 1

c ) 0

4) 0.5

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