Suppose that we define the function f as follows: f(x) = v2x + 5 whenever x is not equal to 10 and f(10) = 20. It is clear that the limit of f(x) , as x approaches 10, is 5. Let E= 0.01 . In other words, in this problem we are given that epsilon is 0.01 . Find the maximum allowable numerical value of d that satisfies the following: if x is in the interval (10-d, 10+d) and x is not equal to 10, then f(x) will be in the interval (5- 0.01, 5 + 0.01) Type the exact answer as a decimal. The maximum allowable numerical value for d is