Suppose that $xN(10,2).$ Find: $($Hint: You need to use table of normal distribution$)$

d$)P(10\mathrm{.}88x13\mathrm{.}22).$

e$)P(|x-10|3).$

f$)$ The value of $x$ for which $P(xx)=0\mathrm{.}81$