Question: Suppose that you are given a decision situation with three possible states of nature: S1, $2, and $3. The prior probabilities are P(S1) = 0.21,

Suppose that you are given a decision situation with three possible states of nature: S1, $2, and $3. The prior probabilities are P(S1) = 0.21, P(S2) = 0.48, and P(53) = 0.31. With sample information I, P(I | S1) = 0.12, P(I | $2) = 0.05, and P(I | 53) = 0.20. Compute the revised or posterior probabilities: P(S1 | D), P(S2 | !), and P(53 | I). If required, round your answers to four decimal places. State of Nature S1 0.2405 52 0.2762 53 0.4833 Total Probability

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