Question: Suppose the following are specified: PG 2 = 0 . 5 , V 2 = 1 . 0 5 , PG 3 = 1 .

Suppose the following are specified:
PG2=0.5, V2=1.05, PG3=1.0, V3=1.06
PL2=0.2, PL3=0.1, PL4=0.5, PL5=0.3, PL6=0.2
QL2=0.1, QL3=0.0, QL4=0.1, QL5=0.1, QL6=-0.1
a) Classify the bus types and write out the power-flow equations.
b) Compute the DC power-flow solution.
c) Starting from the DC power-flow solution, implement the Newton-Algorithm till all the power mismatch errors are smaller than 0.001 pu. How many iterations does it take to reach convergence?
d) Starting from the DC power-flow solution, implement the fast decoupled power-flow algorithm until all the power mismatches are smaller than 0.001 pu. How many iterations does it take to reach the convergence?
e) Repeat parts b, c and d, when each of the loads PLi and QLi and generations PGi specified become twice the previous values. Comment on your result.
My current code: function [ybus, P_eq, Q_eq, theta]= power_flow_analysis()
% Form Ybus matrix and return power flow equations, including DC power flow solution
% Line data: [from_bus, to_bus, R, X, B/2]
linedata =[140.000.300.00;
240.000.200.00;
450.000.400.00;
450.000.400.00;
530.000.300.00;
560.000.300.00];
fb = linedata(:,1); % From bus
tb = linedata(:,2); % To bus
r = linedata(:,3); % Resistance
x = linedata(:,4); % Reactance
b = linedata(:,5); % Line charging
z = r +1i * x; % Impedance
y =1./ z; % Admittance
b =1i * b; % Ground admittance
nbus = max(max(fb), max(tb)); % Number of buses
nbranch = length(fb); % Number of branches
ybus = zeros(nbus, nbus); % Initialize Ybus matrix
% Off-diagonal elements
for k =1:nbranch
ybus(fb(k), tb(k))= ybus(fb(k), tb(k))- y(k);
ybus(tb(k), fb(k))= ybus(fb(k), tb(k)); % Symmetric entry
end
% Diagonal elements
for m =1:nbus
for n =1:nbranch
if fb(n)== m || tb(n)== m
ybus(m, m)= ybus(m, m)+ y(n)+ b(n);
end
end
end
% Display the Ybus matrix
disp('Ybus Matrix:');
disp(ybus);
% Form the power flow equations for real (P) and reactive (Q) power
[P_eq, Q_eq]= form_power_flow_equations(ybus);
disp('Real Power Equations (P):');
disp(P_eq);
disp('Reactive Power Equations (Q):');
disp(Q_eq);
% DC Power Flow Solution with specified power and voltage values
theta = dc_power_flow(ybus);
disp('DC Power Flow Voltage Angles (theta in radians):');
disp(theta);
end
function [P_eq, Q_eq]= form_power_flow_equations(ybus)
% Retrieve power flow equations (real and reactive)
n = size(ybus,1); % Number of buses
V = sym('V',[n,1], 'real'); % Voltage magnitudes
theta = sym('theta',[n,1], 'real'); % Voltage angles
% Initialize symbolic power equations
P_eq = sym(zeros(n,1));
Q_eq = sym(zeros(n,1));
for i =1:n
for j =1:n
if i ~= j
% Contributions to P_i and Q_i from bus j
P_eq(i)= P_eq(i)+ V(i)* V(j)*...
(real(ybus(i, j))* cos(theta(i)- theta(j))+...
imag(ybus(i, j))* sin(theta(i)- theta(j)));
Q_eq(i)= Q_eq(i)+ V(i)* V(j)*...
(real(ybus(i, j))* sin(theta(i)- theta(j))-...
imag(ybus(i, j))* cos(theta(i)- theta(j)));
else
% Diagonal self-contribution
P_eq(i)= P_eq(i)+ V(i)^2* real(ybus(i, i));
Q_eq(i)= Q_eq(i)- V(i)^2* imag(ybus(i, i));
end
end
end
% Simplify equations for better readability
P_eq = simplify(P_eq);
Q_eq = simplify(Q_eq);
end
function theta = dc_power_flow(ybus)
% Compute DC power flow solution (angles only)
% Known values for power generation and loads
PG =[0; 0.5; 1.0; 0; 0; 0]; % Real power generation at buses 1 to 6
PL =[0; 0.2; 0.1; 0.5; 0.3; 0.2]; % Real power load at buses 1 to 6
% Net power injections P = PG - PL
P = PG - PL;
P(1)=0; % Slack bus power set to 0 for DC power flow
% Convert Ybus to susceptance matrix B (ignore resistance)
B =-imag(ybus);
% Remove the slack bus (assume bus 1 as the slack bus)
B_reduced = B(2:end, 2:end);
P_reduced = P(2:end);
% Solve for voltage angles theta (excluding the slack bus)
theta_reduced = B_reduced \ P_reduced;
% Append the slack bus angle (theta1=0)
theta =[0; theta_reduced];
end
Suppose the following are specified: PG 2 = 0 . 5

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