Suppose the following program crashes without producing any output from the printf() statements whatsoever. Which of the following options is the most likely reason the program crashed?

1: #include 2: 3: int main(void) 4: { 5: int q; 6: int *p; 7: 8: printf("Variables are declared."); 9: 10: *p = q; 11: 12: printf("Variable assignment is complete."); 13: 14: return 0; 15: }

The program crashed on line 5 because q cannot be used as the name of an integer variable. This variable name is traditionally reserved for pointers in C.

The program crashed on line 6 because p was not initialized to NULL.

The program crashed on line 6 because p contained a garbage value that pointed outside the bounds of the program's memory.

The program crashed on line 6 because the system cannot create a pointer if you don't #include at the top of the source file.

The program crashed on line 8 because there was no ' ' at the end of the output string, and printf() often crashes if you don't terminate your output strings with a newline character.

The program crashed on line 8 because you cannot make any function calls in a program until all your pointers are properly initialized.

The program crashed on line 10 because q has not been dynamically allocated with malloc().

The program crashed on line 10 because q was uninitialized, and dereferencing an uninitialized pointer can take you out of bounds in memory.

The program crashed on line 10 because p was uninitialized, and dereferencing an uninitialized pointer can take you out of bounds in memory.

The program crashed on line 12 because of how printf() statements interact with pointers.

The program crashed on line 12 because the printf() buffer got too full. If you don't terminate your printf() strings with newline characters (' '), you need to remember to regularly flush it out manually using the fflush() function.

The program crashed on line 14, because returning 0 tells the system that the program failed. As a result, no output was produced. The program should return 1 to indicate successful completion, and that will cause the output to print to the screen.