Suppose the function $g$ statisfies

$\underset{x-3}{lim}g(x)\underset{x-3}{lim}-12x-2x^2-21\underset{x-3}{lim}{x}^2+6x+6\underset{x-3}{lim}g(x)=-12x-2x^2-21$

$We$ want $to$ use the Squeeze Theorem $to$ evaluate $\underset{x-3}{lim}g(x).$

First evaluate: $\underset{x-3}{lim}-12x-2x^2-21$

Next evaluate: $\underset{x-3}{lim}{x}^2+6x+6$

Therefore, $by$ the Squeeze Theorem, $\underset{x-3}{lim}g(x)=$