Question: Suppose the memory cells at address 1 0 through 1 B in the machine language described in appendix C contain the following bit pattern (
Suppose the memory cells at address through B in the machine language described in appendix C contain the following bit pattern the adjacent figure The program counter contains AddressValueAACB a Fill in the table below with the contents of the Program Counter PC and Instruction Register IR after each instruction execution pts: STEP PCIRExecution PC R A Page of CSCI Assessment V Fall a What is the final bit pattern value of each if the following pts Register Register Register Content of PC registerBit pattern of memory of the address b Determine if an overflow occurs when adding the values in registers and in step ptsTranslate the following instructions based on Appendix C: Load the bit pattern from memory cell CD into register A: Store the bit pattern from register into memory cell EF: Add the bit patterns in registers B and C and store the result in register A: Rotate the bit pattern in register B one bit to the right times: Load the immediate value F into register : Question BONUS pts: Page of CSCI Assessment V Fall APPENDIX C Opcode Operand DescriptionRXY LOAD the register R with the bit pattern found in the memory cell whose address is XY RXY LOAD the register R with the bit pattern XY RXY STORE the bit pattern found in register R in the memory cell whose address is XYRS MOVE the bit pattern found in register R to register S RST ADD the bit patterns in registers S and T as though they were twos complement representations and leave the result in register R RST ADD the bit patterns in registers S and T as though they represented values in floatingpoint notation and leave the floatingpoint result in register R RST OR the bit patterns in registers S and T and place the result in register R RST AND the bit patterns in register S and T and place the result in register R RST EXCLUSIVE OR the bit patterns in registers S and T and place the result in register RA RX ROTATE the bit pattern in register R one bit to the right X times. Each time place the bit that started at the loworder end at the highorder end.B RXY JUMP to the instruction located in the memory cell at address XY if the bit pattern in register R is equal to the bit pattern in register number Otherwise, continue with the normal sequence of execution. The jump is implemented by copying XY into the program counter during the executeC HALT execution. Can you tell me a second part of a from where you get the register
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