Part A - Molar solubility I

Lead iodide is almost insoluble. The equilibrium in a saturated solution of PbI₂ is:

PbI_2(s) ⇌ Pb²⁺_(aq) + 2I^–_(aq)

At a particular temperature, the concentration of lead ions in a saturated solution of lead iodide was found to be 2.02×10⁻³ M

What is the solubility of lead iodide expressed as mol/L (the molar solubility)?

Lead iodide is almost insoluble. The equilibrium in a saturated solution of PbI₂ is:

PbI_2(s) ⇌ Pb²⁺_(aq) + 2I^–_(aq)

At a particular temperature, the concentration of lead ions in a saturated solution of lead iodide was found to be 2.02×10⁻³ M

What is the solubility of lead iodide expressed as mol/L (the molar solubility)?

2.02×10⁻³ M

3.93 x 10^-2 M

1.26 x 10^-3 M

1.96 x 10^-3 M

 

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ANSWER 196 x 103 M CALCULATION We can use the expression for Ksp to calculate the ... View the full answer