Suppose we have a whirling string $($spinning around its axis$)$ of length $7$ meters, linear density $0\mathrm{.}03$ kilograms per meter, spinning at angular velocity $6$ radians per second.

Suppose it is popped out completely $($it never crosses the axis, only at the endpoints$).$ What is the tension on the string in Newtons?

Tension:

$6^2*7*(\mathrm{.}03*6)$ help $($numbers$)$