Suppose we have the following Java classes: public class Foo {private String mystring; public Foo (String m) {this.mystring = m;} public int length() {return this.mystring.length();}} public class Bar extends Foo {private String str; public Bar (String s1, String s2) {super (s1); this.str = s2;} public int length() {return this.str.length();} public String geeStr() {return this.str;}} public class FooUtils {public void fooCheck (Foo f) {System.out.println ("It's a Foo!");} public void fooCheck (Bar b) {System.out.println ("It's a Bar!"+b.getStr());}} a. As discussed in class, if we removed the call to super (s1) n the constructor for Bar, this code would not compile. Explain in 1-3 short sentences what the call to super (s1) does in the constructor for Bar and why it is necessary here