Suppose we have two computers: A and B$.$

Computer A executes a program with an average CPI of $1\mathrm{.}8.$

Computer B executes the same program with $30\%$ fewer instructions and with a CPI of $1\mathrm{.}4$ at $900Mhz.$

In order for the two computers to have the same performance, what does the clock rate of the computer A need to be$?$

CPU Time $=\frac{\text{I}\text{n}\text{s}\text{t}\text{r}\text{u}\text{c}\text{t}\text{i}\text{o}\text{n}\text{C}\text{o}\text{u}\text{n}\text{t}(IC)*Cycles\text{p}\text{e}\text{r}\text{I}\text{n}\text{s}\text{t}\text{r}\text{u}\text{c}\text{t}\text{i}\text{o}\text{n}(CPI)}{\text{C}\text{l}\text{o}\text{c}\text{k}\text{R}\text{a}\text{t}\text{e}(Hz)}$

$1\mathrm{.}6$ Ghz

$3\mathrm{.}2$ Ghz

$16Mhz$

$320Mhz$