Question: Suppose we know Herbrand's theorem, that is , that a formula in clausal normal form is satisfiable if and only if it has a Herbrand

Suppose we know Herbrand's theorem, that is, that a formula in clausal normal form is satisfiable if and only if it has a Herbrand model. Can we use this theorem (along with other basic techniques we have discussed) to prove that the Bernays-Shoenfinkel fragment of FOL is decidable?

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