Question: Suppose we transmit a packet and the final byte (the checksum) of the unmodified packeting strategy is lost by the receiver. Immediately after the transmission,

Suppose we transmit a packet and the final byte (the checksum) of the unmodified packeting strategy is lost by the receiver. Immediately after the transmission, another packet is sent and the receiver interprets the start byte of the 2nd packet as the checksum of the previous one. What are the odds that the receiver would incorrectly interpret the first packet as valid? What would be the odds for the modified (16-bit) protocol?

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