Suppose $x>0,$ find the area bounded between the curves $f(x)=\frac{1}{x}$ and $g(x)=\frac{1}{6}(-x^2+7).$

$\frac{7}{9}-ln(2)$

$\frac{ln(2)}{3}-\frac{5}{11}$

$\frac{4}{5}-ln(2)$

$\frac{5}{11}-ln(2)$

$\frac{4}{5}+ln(2)$