Question: Suppose X is a normal random variable with mean = 90 and standard deviation = 9. Find b such that P(90 X b) = 0.3.

Suppose X is a normal random variable with mean = 90 and standard deviation = 9. Find b such that

P(90 X b) = 0.3.

(Round your answer to one decimal place.)

2. Suppose X is a normal random variable with mean = 100 and standard deviation = 10. Find a such that

P(X a) = 0.03.

(Round your answer to one decimal place.)

3.LSAT test scores are normally distributed with a mean of 157 and a standard deviation of 5. What score would place you in the top 2% of test-takers? (Round your answer to the nearest whole number.)

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