Suppose you have a pendulum clock which keeps correct time on Earth $($acceleration due to gravity $=9\mathrm{.}8$ m$/$s$?).$ Without changing theclock, you take it to the Moon $($acceleration due to gravity $=1\mathrm{.}6$ m$/$s$?).$ For every hour interval $($on Earth$)$ the Moon clock will record: $1$h$0$ V$1\mathrm{.}6/9\mathrm{.}8$h $(1\mathrm{.}6/9\mathrm{.}8)$ h$0$ V$9\mathrm{.}8/1\mathrm{.}6$h$0(9\mathrm{.}8/1\mathrm{.}6)$ h