Question: Suppose you run k - means using k = 3 and k = 5 . You find that the cost function is much higher for
Suppose you run kmeans using k and k You find that the cost function is much
higher for k than k at convergence. What can you conclude?
a This is mathematically impossible. There must be a bug in the code.
b kmeans got stuck in a bad local minimum when k You should try rerunning kmeans
for k with a different initialization.
c kmeans got lucky when k You should try rerunning kmeans for k with different
initializations, until it performs no better than k
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