${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(t^4+2t^3+t^2-t+5)e^{3t}dt$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}se{n}^{6}co{s}^{3}d$

Resolve the following with this instructions:

using integration $by$ parts and evaluating integrals using the tabulation method