Question: t3 Non-conserved Forces In the previous section. we assumed that all of the forces acting on the skater were conservative. This is not very realistic.

 t3 Non-conserved Forces In the previous section. we assumed that all

t3 Non-conserved Forces In the previous section. we assumed that all of the forces acting on the skater were conservative. This is not very realistic. To see this, choose the intro option in the simulation again and place the skater on the u-shaped track. The skater will then oscillate back and forth. In this setup. do you expect them to stop eventually? A v To simulate a more realistic situation. put some small amount of friction in the system using the fn'ction option. Do you expect the skater to come to a stop now? A . v In the simutation, we used a \"feature" to include friction. However, it's important to think about what this means. Where is the friction coming from? Would there be more than one nonconservative force acting in real life? Accounting for all the energy is important, but not always obvious in how we represent this. For example, select the playground option and resetthe simulation, ensure that the Friction option is set to None. Now, expand the energy table option and create a simple track that lets the skater fall from some height. An example setup is shown below: Restart Ektar to PithTE Let the skater run off of the track and fall to the ground. Pay attention to the energy graph. What kinds of energy exist? (Select all that apply.) 0 Potential Energy 0 Thermal Energy 0 Kinetic Energy 0 Total Energy Does this make sense? Where could the Energy represented in the graph come from? We say a system is closed if there is no gaintloss of energy in the system. In a closed system, Total Energy is Conserved. i.e. (Change in KE) + (Change in PE) + (Change in TE] = 0. where TE is \"Thermal Energy." This often represents the energy lost to vibrations, mass changes. temperature changes, etc. In the previous example, there was a conversion of energy from KE to TE. What did the simulation convert to TE? A .H v It's important to remember that when solving problems Energy can't just "disappear." You must account for all of the Energy in a System

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