Question: Table 1: Inelastic Collisions Table 1a: Both masses are equal. The initial velocities are equal and opposite. m 1 v 1i p 1i v 1f
Table 1: Inelastic Collisions
| Table 1a: Both masses are equal. The initial velocities are equal and opposite.
| ||||
| m1 | v1i | p1i | v1f | p1f |
|
1.50 Kg
|
1 m/s |
1.5 kg m/s |
0 m/s |
0 kg m/s |
| m2 | v2i | p2i | v2f | p2f |
|
1.50kg
|
-1m/s |
-1.5 kg m/s |
0m/s |
0 kg m/s |
| Total Eki | Total Ekf | Ekf/Ekias % | p1i + p2i | p1f + p2f |
|
1.50 J
|
0 J |
0 % |
| Table 1b: mass 1 is larger than mass 2. The initial velocities are equal in magnitude and opposite in direction.
| ||||
| m1 | v1i | p1i | v1f | p1f |
|
2 kg
|
1 m/s |
2 kg m/s |
0.14 m /s |
0.29 kg m/s |
| m2 | v2i | p2i | v2f | p2f |
|
1.5 kg
|
-1 m/s |
-1.5 kg m/s |
0.14 m/s |
0.21 kg m/s |
| Total Eki | Total Ekf | Ekf/Ekias % | p1i + p2i | p1f + p2f |
|
1.75 J
|
0.04 J |
| Table 1c: Both masses are equal. The initial velocities are of the same direction, but mass 1 has a larger magnitude of initial velocity.
| ||||
| m1 | v1i | p1i | v1f | p1f |
|
1.50 kg
|
1.50 m/s |
2.25 kg m/s |
0.75 m/s |
1.33 kg m/s |
| m2 | v2i | p2i | v2f | p2f |
|
1.50 kg
|
0.50 m/s
|
0.75 kg m/s |
1.25 m/s |
1.88 kg m/s |
| Total Eki | Total Ekf | Ekf/Ekias % | p1i + p2i | p1f + p2f |
|
1.88 J
|
1.59 J |
Which of the following values are roughly equal (within 0.01) in all cases? Explain using your examples.
v1fand v2f
p1i + p2iand p1f + p2f
Total Eki and Total Ekf
Table 2: In-Between Collision
| Table 2a: Both masses are equal. The initial velocities are equal and opposite.
Elasticity value: 50 %
| ||||
| m1 | v1i | p1i | v1f | p1f |
|
1.5 kg
|
1.5 m/s |
2.25 kg m/s |
-0.75m/s |
-1.13 kg m/s |
| m2 | v2i | p2i | v2f | p2f |
|
1.5 kg
|
-1.5 m/s |
-2.25 kg m/s |
0.75 m/s |
1.13 kg m/s |
| Total Eki | Total Ekf | Ekf/Ekias % | p1i + p2i | p1f + p2f |
|
3.38 J
|
0.84 J |
| Table 2b: mass 1 is larger than mass 2. The initial velocities are equal in magnitude and opposite in direction.
Elasticity value: 50 %
| ||||
| m1 | v1i | p1i | v1f | p1f |
|
2 kg
|
1.5 m/s |
3 kg m/s |
-0.43 m/s |
-0.86 kg m/s |
| m2 | v2i | p2i | v2f | p2f |
|
1.5 kg
|
-1.5 m/s |
-2.25 kg m/s |
1.07 m/s |
1.61 kg m/s |
| Total Eki | Total Ekf | Ekf/Ekias % | p1i + p2i | p1f + p2f |
|
3.94 J
|
1.04 J |
| Table 2c: Both masses are equal. The initial velocities are of the same direction, but mass 1 has a larger magnitude of initial velocity.
Elasticity value: 50 %
| ||||
| m1 | v1i | p1i | v1f | p1f |
|
1.5 kg
|
2.5 m/s |
3.75 kg m/s |
1.75m/s |
2.63 kg m/s |
| m2 | v2i | p2i | v2f | p2f |
|
1.5 kg
|
1.5 m/s |
2.25 kg m/s |
2.25 m/s |
3.38 kg m/s |
| Total Eki | Total Ekf | Ekf/Ekias % | p1i + p2i | p1f + p2f |
|
6.38 J
|
6.09 J |
Which of the following values are roughly equal (within 0.01) in all cases? Explain using your examples.
v1fand v2f
p1i + p2iand p1f + p2f
Total Eki and Total Ekf
True or False: A collision with an elasticity of X% means that the final total kinetic energy is always equal to X% of the initial total kinetic energy. Explain your answer using examples.
True or False: Consider two collisions with the same values for initial total kinetic energy and elasticity (not 0% or 100%) but with two different masses. Does the same % of total kinetic energy remain after the collision? Show how you came up with your answer by providing two more examples.
Please answers all of the questions with an example, and explanation.
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