+ Table 2: f = 4.50 cm Object Height = 1.00 cm (8 points) Actual Actual Actual Object Distance Actual mage Experimental Theoretical Trial Image 1/q p or do (cm) 1/p Distance Height Magnification Magnification q or di hi (cm) Mexperimental Mtheoretical Nominal Actual 1 3.25 3.25 -11.66 3.59 -0.09 0.30 3.59 3.59 2 3.00 3.00 -9.01 3.00 0.11 0.33 3.00 3.00 3 2.75 2.76 -7.13 2.59 -0.14 0.36 2.59 2.58 A 2.50 2.50 -5.65 2.26 -0.18 0.40 2.26 2.26 5 2.25 2.25 -4.50 2.00 -0.22 0.44 2.00 2.00 6 2.00 2.00 3.60 1.80 -0.28 0.50 1.80 1.80 7 1.75 1.74 2.83 1.63 -0.35 0.57 1.63 1.63 8 1.50 1.51 2.26 1.50 -0.44 0.66 1.50 1.50 9 1.25 1.25 -1.73 1.39 -0.58 0.80 1.39 1.38 9 10 1.00 1.00 -1.29 1.29 -0.78 1.00 1.29 1.29 11 0.75 0.74 0.89 1.20 -1.12 1.35 1.20 1.20 12 0.50 0.49 -0.54 1.12 -1.85 2.04 1.12 1.10 Complete Table 1 by calculating the Theoretical Magnifications for each of the object distances. Show work for one of the Theoretical Magnifications. (2 points) One of the Theoretical Magnifications: -9.01 3.00 3. 00Mtheoretical1. Using Excel, or some other graphing program, make a graph of Magnification vs. Image Distance (M vs. q). Add the trendline and display the equation on the chart. (5 points) M vs. q 3.5 3 2.5 2 1.5 y = -0.222x + 1.0022 0.5 U -14 -12 -10 -8 -6 -4 -2 a 2. What physical property of the lens does the absolute value of the slope represent? (5 points) 3. Using Excel, or some other graphing program, make a graph of 1/q vs 1/p. Add the trendline and display the equation on the chart. (5 points)2 2.5 "0., y = 4.0098): + 0.2247 1/q ,'_. 4. What physical property of the lens does the y-interCEpt represent? (5 points) 5. Write a short, general statement about the image that is produced when the object is placed between the focal point and the lens. Your statement must contain three characteristics (i.e., type, orientation, size, etc.) about the image to receive full credit. (10 points)