Table $5-4$ shows a sequence that simplifies the $2-$of$-3$ voting to its minimum SOP form, but you must determinethe rule or law that validates each step.

Begin with the Boolean expression in the first row of Table $5-4.$

Indicate the Boolean rule or law in Table $5-3$ that is applied to derive the new expression for each row of Table $5-4($the first two simplifications are done for you$)$

Continue through the table, indicating the Boolean rule or law that is applied at each step to simplify the $2-$of$-3$ voting logic to its minimum SOP form.

Table $5-4$: Boolean Algebra Simplification of $2-$of$-3$ Voting Logic

$\backslash$table$[[$Step$,$Boolean Expression,$\backslash$table$[[$Boolean Rule$],[$or Law$]],$Step,$\backslash$table$[[$Boolean$],[$Expression$]],\backslash$table$[[$Boolean Rule$],[$or Law$]]],[1,A^{\text{'}}BC+A{B}^{\text{'}}C+AB{C}^{\text{'}}+$ABC,Starting form,$8,A^{\text{'}}BC+AB+AC,$Distributive Law$],[2,A^{\text{'}}BC+A{B}^{\text{'}}C+AB(C^{\text{'}}+C),$Distributive Law,$9,(A^{\text{'}}C+A)B+AC,$Distributive Law$],[3,A^{\text{'}}BC+A{B}^{\text{'}}C+AB*1,$Rule $6,10,(A+A^{\text{'}}C)B+AC,$Commutative Law$],[4,A^{\text{'}}BC+A{B}^{\text{'}}C+AB,$Rule $4,11,(A+C)B+AC,$Rule $11],[5,A^{\text{'}}BC+A(B^{\text{'}}C+B),$Distributive Law,$12,AB+CB+AC,$Distributive Law$],[6,A^{\text{'}}BC+A(B+B^{\text{'}}C),$Commutative Law,$13,AB+BC+AC,$Commutative Law$],[7,A^{\text{'}}BC+A(B+C),$Rule $11,]]$

What does the final logic expression indicate?