$\backslash$table$[[$Entered$,$Answer Preview,Result$],[(\frac{1}{t})+[\frac{4}{t^2}],\frac{1}{t}+\frac{4}{t^2},$incorrect$]]$

The answer above is NOT correct.

$(1$ point$)$ Solve the following initial value problem:

$t\frac{dy}{dt}+2y=1t$

with $y(1)=5.$

$($Find $y$ as a function of $t.)$

$y=$