Question: table [ [ From Te , Materials,Welding,Drills Lathes,Grinders Benders,, ] , [ Materials , 0 , 8 0 , 5 0 , 0 ,

\table[[From Te,Materials,Welding,Drills Lathes,Grinders Benders,,],[Materials,0,80,50,0,0,45],[Welding,25,0,0,55,0,0],[Drills,30,0,0,0,55,0],[Lathes,0,30,0,0,15,0],[Grinders,45,0,70,0,0,0],[Benders,15,0,15,0,0,0]]
\table[[,1,2,3,4,5,6],[1,-,20,40,20,40,60],[2,-,-,20,40,20,40],[3,-,-,-,60,40,20],[4,-,-,-,-,20,40],[5,-,-,-,-,-,20],[6,-,-,-,-,-,-]]
Based on the flows shown in the matrix, it is likely that the processes Drills and Grinders are in rooms next to each other as they have the highest numb moves between each other.
Based on the flows shown in the matrix, it is likely that the processes Materials and Welding are in rooms next to each other as they have the second his number of moves between each other.
One of the layouts that could be designed is:
\table[[Room 1= Benders,Room 2= Materials,Room 3= Welding],[Room 4= Drills,Room 5= Grinders,Room 6= Lathes]]
The cumulative distance based on the overall movement of material between processes for this layout =q, feet (enter your response as a whole number).
 \table[[From Te,Materials,Welding,Drills Lathes,Grinders Benders,,],[Materials,0,80,50,0,0,45],[Welding,25,0,0,55,0,0],[Drills,30,0,0,0,55,0],[Lathes,0,30,0,0,15,0],[Grinders,45,0,70,0,0,0],[Benders,15,0,15,0,0,0]] \table[[,1,2,3,4,5,6],[1,-,20,40,20,40,60],[2,-,-,20,40,20,40],[3,-,-,-,60,40,20],[4,-,-,-,-,20,40],[5,-,-,-,-,-,20],[6,-,-,-,-,-,-]] Based on the flows shown in

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