Question: table [ [ Let , x 1 = Number of stuffed bears,,,,, ] , [ x 2 = Number of stuffed rabbits,,,,, ] ,

\table[[Let,x1= Number of stuffed bears,,,,,],[x2= Number of stuffed rabbits,,,,,],[x3= Number of stuffed dogs,,,,,],[x4= Number of stuffed cats,,,,,],[The LP Model,PRODUCTS,,,],[,,],[Constraint 1,3,1,,1,,7,,\table[[Available],[100]],\table[[RESOURCES],[Stuffing in pounds]]],[Constraint 2,2,2,,3,,,,100250,Yards of fabric],[Constraint 3,4,2,,1,,2,,300,Assembly time in hours],[Constraint 4,1,4,,2,,3,,200,Pieces of trim],[Profit/unit,8.00,5.00,$,6.00,$,4.00,,,]]
a. Solve the above Linear programming problem and obtain sensitivity analysis.
DO NOT CHANGE ANY OF THE UNITS
Use your sensitivity output to answer the following questions.
b. Which constraints are(is) non-binding and what does it mean?
c. If the profit per unit of stuffed rabbits is increased by $2, will the optimal solution change?
What would be the new value of the objective function? Give the new value here
d. As you note, at optimum no stuffed cats (x4) are being produces.
What should the profit per unit of stuffed cats (X4), so it becomes profitable to produce it? Explain how you arrived at the value.
e. Fifty yards of fabric can be obtained at 1.20 above the current cost.
Should the additional yards of fabric be obtained at the quoted cost? Why or why not? Fully explain.
 \table[[Let,x1= Number of stuffed bears,,,,,],[x2= Number of stuffed rabbits,,,,,],[x3= Number of

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