Question: table [ [ Room , Room,Room ] , [ 1 , 2 , 3 ] , [ Room , Room,Room ] , [ 4

\table[[Room,Room,Room],[1,2,3],[Room,Room,Room],[4,5,6]]
His foreman has completed a month-long study of the number of loads of material that have moved from one process to another in the current building. This information is contained in the flow matrix below. Finally, Creasey also developed a matrix to indicate distances between the work areas shown in the building schematic, shown on the right below
\table[[From-Ie,Materials,Welding,Drills,Lathes,Grinders,Benders],[Materials,0,80,55,0,0,50],[Welding,30,0,0,55,0,0],[Drills,30,0,0,0,55,0],[Lathes,0,20,0,0,15,0],[Grinders,50,0,70,0,0,0],[Benders,15,0,20,0,0,0]]
\table[[,1,2,3,4,5,6],[1,-,20,40,20,40,60],[2,-,-,20,40,20,40],[3,-,-,-,60,40,20],[4,-,-,-,-,20,40],[5,-,-,-,-,-,20],[6,-,-,-,-,-,-]]
Based on the flows shown in the matrix, it is likely that the processes Drills and Grinders are in rooms next to each other as they have the highest number of moves between each other
Based on the flows shown in the matrix, it is likely that the processes Materials and Welding are in rooms next to each other as they have the second highest number of moves between each oth One of the layouts that could be designed is:
\table[[Room 1= Benders,Room 2= Materials,Room 3= Welding],[Room 4= Drills,Room 5= Grinders,Room 6= Lathes]]
The cumulative distance based on the overall movement of material between processes for this layout = feet (enter your response as a whole number).
 \table[[Room,Room,Room],[1,2,3],[Room,Room,Room],[4,5,6]] His foreman has completed a month-long study of the number

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