$\backslash$table$[[\backslash$table$[[=$ today$()],[=$ days $360($start date, end date$)],[=$networkdays$($start date,end date$)]],\backslash$table$[[=$ upper$($cell range$)],[=$ left$($text$,$ find$($find$,$text, within text$)-1)],[=$ right$($text$,$len$($text$)-$find$($find text,within text$))]]],[$A$,$A$,B,$c$,$D$,$E$,$F$,$G$,H,1,1],[\frac{1}{2},$Employee,$\backslash$table$[[$Today Date:$],[$Full Name$]],\backslash$table$[[4/7/2016],[$Last Name$]],,,$G$-$Caps,Hire date,Service Years,Salary.,In of Work Days$],[3,10000,\backslash$table$[[$Full Name$],[$Aikman$,$Gary$]],\backslash$table$[[$Last Name$],[$Aikman$]],\backslash$table$[[$First Name$],[$Gary$]],\frac{\text{G}\text{e}\text{n}\text{d}\text{e}\text{r}}{f},\frac{G-\text{C}\text{a}\text{p}\text{s}}{F},\frac{1}{1}\frac{?}{2000},16\mathrm{.}27,41800,4244],[4,10166,$Fishe,Bryan,$\backslash$table$[[$Aikman$],[$Fishe$]],$Bryan,$f,F,\frac{2}{15}\frac{?}{1998},18\mathrm{.}14,51300,4734],[5,10387,$Felser,Cynthia,Felser,Cynthia,$f,F,\frac{3}{22}\frac{?}{1992},24\mathrm{.}04,40900,6274],[6,10398,$Parsley, Gwen,Parsley,Gwen,$m,M,\frac{2}{22}\frac{?}{1998},18\mathrm{.}13,74200,4729],[7,10552,$Leslic,jean,Leslic:,Jean,f$,F,\frac{6}{8}\frac{?}{1991},24\mathrm{.}83,48500,6479],[8,10640,$Imber, Cynthia,Imber,Cynthid,$m,$M$,\frac{10}{29}\frac{?}{1993},22\mathrm{.}44,43500,5855],[9,10710,$Granger,Kevin,Granger,Kevin,$m,M,\frac{4}{22}\frac{?}{1993},22\mathrm{.}96,20500,5991],[10,10785,$Dunes, Annette,Dunes,Annette,$f,F,\frac{4}{27}\frac{?}{1984},31\mathrm{.}94,42600,8335],[11,10936,$Cusak, Barbara,Cusak,Barbara,f$,$F$,\frac{8}{8}\frac{?}{1985},30\mathrm{.}66,32800,8001]]$

Enter the correct formula for cell $H3$ that calculates the years of services the date in cell C$1$ and G$3$ to calculate the number of days the divide by $360$ to get the years. Use absolute addressing when referencing todays date.