Table x 0 1 2 x -2 1 0 y 1 und -2 ( x- 2)(x+ 1) y und 0 1 Equation A Equation B y? =x-1 Graph A if . .. Graph B ASSESSMENT (Optional) Practice Performance Task Complete the following problems. Show all your work. Matching Functions Directions: On the next page are (7) graphs, (7) equations, (7) tables, and (7) unique properties. Your performance task is to match the equation, table, and rule to the correct graph. 1. Record your answers in the table below. One has already been done for you. Property Graph Equation Table A B C D E D 9 G 2. Explain how you matched each graph to its equation. Graph A Graph B Graph C Graph D Graph E Graph F Graph Fis a line, so it fits equation D. In the equation y = =x - 2, I know the "-2" represents the y- intercept . Graph F is the only function with a y-intercept of - 2 . Graph G lifelong Algebra 2A LEP 5 L4L - Algebra ZA (2020) Page / 48ur work. Table e has already been done for you. , and rule to the correct graph. tice Performance Task equations, (7) tables, and (7) unique properties. Your Property Graph A Equation A Table A Property A . . . .. y = (x - 2) (x + 1) y und o 1.41 1.73 2 y is the same as the cube root of x Graph B Equation B Table B Property B yz =x- 1 x -2 - 1 0 1 2 y is the same as 1 plus y 1 und -2 -2 und the square root of x raph C Equation C Table C Property C y=-2x2- x+6 X - 2 - 1 0 1 2 3 y is the same as x cubed y 0 5 6 3 Graph D Equation D Table D Property D x -2 -1 0 1 2 3 x # -1 and x #2 y + 2 = 3x y - 8 - 1 0 1 8 27 24 43 2 10 1 1 3 4 5. Graph E Equation E Table E Property E X - 6 - 3 0 3 6 9 xs = y y - 4 -3 - 2 - 1 0 1 has exactly two roots 1 23 4 5 Graph F Equation F Table F Property F x -27 -1 0 1 8 27 ( y - 1)2 = x - 3 - 1 0 1 2 3 Domain: {x|x 2 1} Range: {yly 2 0} Graph G Equation G Table G Property G X - 2 -1 0 1 2 4 y ' = x y und und 1 2 2.41 3 y - intercept at (0, -2) x - intercept at (6,0) lifelong Algebra 2A LEP 5 L4L - Algebra ZA (2020) Page | 49